洛谷题普及- 数学原理：2个集合内所有数相加相乘结果一样

a=123
while 123<=a<=333:
    b=2*a
    c=3*a
    if (a//100)+(a//10)%10+a%10+(b//100)+(b//10)%10+b%10+(c//100)+(c//10)%10+c%10==45 and (a//100)*((a//10)%10)*(a%10)*(b//100)*((b//10)%10)*(b%10)*(c//100)*((c//10)%10)*(c%10)==2*3*4*5*6*7*8*9:
        print(a,b,c)
    a+=1