m=int(input()) e=1 for i in range(m):

x=input().split()
num=[]
for a in x:
    num.append(int(a))
d=len(num)
for b in range(1,d):
    count=0
    for c in range(b,d):
        if num[b]==num[c]:
            count+=1
    if count%2!=0:
        print(f"No{e}. The odd integer is: {num[b]}.")
        break
    else:
        continue
e+=1

因为解答错误。对测试点一，一个询问的答案是 1000，你的输出是 4。

参考 AC 代码：

for h in range(int(input())):
    x = [int(i) for i in input().split()][1:]
    times = [0 for i in range(max(x)+1)]
    for i in x:
        times[i] += 1
    for i in x:
        if times[i]%2:
            print('No%d. The odd integer is: %d.'%(h+1,i))
            break